My Impedance, from what i calculated, was 20+40j. I know power is V^2/2R. and my w = 2pi(400) = 800pi. Can i get some help?
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You have the impedance (R) in complex form. This part is done.That's what the problem is asking to find.
10e^(j27°) this is Phasor Representation.so if my impedence is 20+40j. And my current is 10cos(wt+27°) = 10e^(j27°). so then my current^2 is 100e^2(j27°) and my power is (20+40j)(100e^2(27°)) Does this seem/sound right?
Yes.Oh i see. So then if i do the math, my current is 8.91+j4.5. if i square this, i get 58.86+80.72j. So then i muliply that by 20+j40?
by Aaron Carman
by Don Wilcher
by Aaron Carman