I am trying to find the equivalent thevenin voltage across ab in the attached ac circuit ,
f=1000Hz
Ra = -34.22+j30.15 Ω
Rc = 90.45+ j102.67 Ω
Z4 = 119 Ω
Vs = 78 + j270 V
Vx = 4 + j140 V
this is what i did just want to make sure if what i am doing is correct, if not please show me the correct way to find Vth.
Zt=Za+Zc+Z4
It = (Vs-Vx)/Zt
Vza = It*Za
Vzc = It*Zc
Vz4 = It*Z4

Eth = Vzc+Vz4-Vx

 

It seems to me:
Vthevenin = Vs
Rthevenin = RA

 

i already took the load out, and the circuit has two ac voltage sources, i think Vth is voltage across ab which contains Rc, Vx and Z4

 

It seems to me:
Vthevenin = Vs
Rthevenin = RA

That would be incorrect.

 

i already took the load out, and the circuit has two ac voltage sources, i think Vth is voltage across ab which contains Rc, Vx and Z4

Ah. Ok. I thought the load was still in.

 

I am trying to find the equivalent thevenin voltage across ab in the attached ac circuit ,
f=1000Hz
Ra = -34.22+j30.15 Ω
Rc = 90.45+ j102.67 Ω
Z4 = 119 Ω
Vs = 78 + j270 V
Vx = 4 + j140 V
this is what i did just want to make sure if what i am doing is correct, if not please show me the correct way to find Vth.
Zt=Za+Zc+Z4
It = (Vs-Vx)/Zt
Vza = It*Za
Vzc = It*Zc
Vz4 = It*Z4

Eth = Vzc+Vz4-Vx

You are almost correct.

It's hard to check your work when you don't indicate the polarity of any of your voltages or currents. That is where you need to start -- annotate your diagram so that these are clear. If you do that, you should see your mistake.

Of course, I'm having to assume things such as the polarity of your two voltage sources. I shouldn't have to be doing that.

 

here is the circuit and i indicated the polarity on it, sorry about that

 

You are almost correct.

It's hard to check your work when you don't indicate the polarity of any of your voltages or currents. That is where you need to start -- annotate your diagram so that these are clear. If you do that, you should see your mistake.

Of course, I'm having to assume things such as the polarity of your two voltage sources. I shouldn't have to be doing that.

here is the circuit and i indicated the polarity on it, sorry about that

Thanks for updating your diagram.

With those annotations, several of your earlier equations are now wrong.

Notice that the current It is going through all of the components in the same direction. But the polarities of your Ra, Rc, and Z4 are not all in the same direction, so some of the voltages need to have the opposite polarity.

You don't indicate what direction It is flowing in and, instead, force the reader to practice either mind reading or reverse engineering. Note that this is NOT the way to impress either a grader or a boss. Doing the reverse engineering, your equation for It implies that It is the current flowing clockwise in the circuit.

This means that

Zt=Za+Zc+Z4
It = (Vs-Vx)/Zt

Vza = -It*Za
Vzc = -It*Zc
Vz4 = It*Z4

Now look at your circuit and see that you have two possible paths to get from a to b. You can compute the voltage drop along either path and they must yield the same result -- the implies a simple way to check your results.

Going up the left branch, we have

Vab = Vs + Vza

Going up the right branch, we have

Vab = Vz4 + Vx - Vza

Are these, in fact, the same? Do the math and see. If you have any problems, post your efforts and we can go from there.

 

Thanks for updating your diagram.

With those annotations, several of your earlier equations are now wrong.

Notice that the current It is going through all of the components in the same direction. But the polarities of your Ra, Rc, and Z4 are not all in the same direction, so some of the voltages need to have the opposite polarity.

You don't indicate what direction It is flowing in and, instead, force the reader to practice either mind reading or reverse engineering. Note that this is NOT the way to impress either a grader or a boss. Doing the reverse engineering, your equation for It implies that It is the current flowing clockwise in the circuit.

This means that

Zt=Za+Zc+Z4
It = (Vs-Vx)/Zt

Vza = -It*Za
Vzc = -It*Zc
Vz4 = It*Z4

Now look at your circuit and see that you have two possible paths to get from a to b. You can compute the voltage drop along either path and they must yield the same result -- the implies a simple way to check your results.

Going up the left branch, we have

Vab = Vs + Vza

Going up the right branch, we have

Vab = Vz4 + Vx - Vza

Are these, in fact, the same? Do the math and see. If you have any problems, post your efforts and we can go from there.

thank you for your help, i did the math and they are indeed the same, but let me make things more clear, i am attaching the real circuit that i started with. I did a delta to wye transformation that's how i got Ra and Rc and after that i tried solving for Vth so i simplified the circuit. so can u check with me please to see if what i did is correct and thank very much for ur time

 

See if what is correct?

You haven't given enough information to determine if your transformation was done correctly or not, let alone if your end result is correct or not.

 

See if what is correct?

You haven't given enough information to determine if your transformation was done correctly or not, let alone if your end result is correct or not.

this is my transformation
Za =(Z1*Z2)/(Z1+Z2+Z3)
Zb =(Z2*Z3)/(Z1+Z2+Z3)
Zc =(Z1*Z3)/(Z1+Z2+Z3)

so can you tell me how to find the thevenin voltage after i take out the load

 

I got Vthevenin=-99.476+19.687j
What have you got?

 

I got Vthevenin=-99.476+19.687j
What have you got?

May not matter what he got. He has someone that worked the problem and posted an answer and so he can, if he wants to, just turn that in without any further work.

This particular OP may not do so, be we certainly get a lot that would.

 

this is my transformation
Za =(Z1*Z2)/(Z1+Z2+Z3)
Zb =(Z2*Z3)/(Z1+Z2+Z3)
Zc =(Z1*Z3)/(Z1+Z2+Z3)

so can you tell me how to find the thevenin voltage after i take out the load

The circuit that you set up looks fine.

 

May not matter what he got. He has someone that worked the problem and posted an answer and so he can, if he wants to, just turn that in without any further work.

This particular OP may not do so, be we certainly get a lot that would.

The suspense was killing me.

 

The circuit that you set up looks fine.

ok the thevenin volt would be either
Eth = Vs+Vza
Eth = -Vzc+Vz4+Vx
like you said, right? or if you walk me thru on how to find it. thank you

 

This is presumably a point at which one might ask the OP to start again and restate the problem with all component values as given in the original problem formulation. I would be reluctant to trust your transformations without the requisite working shown. Where is node "a" in the original circuit attached in post #9? What are the values of Z1, Z2, Z3 & Z5?

I'm curious that you can obtain an impedance with a negative real part [see "Rc"] when the circuit offers no clue as to how this has arisen.

 

ok the thevenin volt would be either
Eth = Vs+Vza
Eth = -Vzc+Vz4+Vx
like you said, right? or if you walk me thru on how to find it. thank you

I already did. See Post #8. See if you can follow where I got everything and then ask specific questions at the points where you can't.

 

thank you guys for the hlep, i am just gonna post a new thread with more details on how i started the problem

 

thank you guys for the hlep, i am just gonna post a new thread with more details on how i started the problem

I don't think there's any need to start a new thread dealing with this same problem. It will just cause confusion as people end up posting to one, the other, or both threads. Let's keep it all in one place, okay?