help time load voltage is out of phase with source

Discussion in 'Homework Help' started by lp84, Feb 6, 2009.

  1. lp84

    Thread Starter New Member

    May 7, 2007
    4
    0
    I have to find how many microseconds the load voltage is out of phase with the source voltage.

    I have the vs = 480sqrt(2)cos(120pi*t+0deg)
    and vl 694.25cos(120pi*t+1.01deg)

    Would solving for t inside the cosine's give me the time out of phase?

    ie. t1 = -0deg/120pi = 0
    t2 = -1.01deg/120pi = -2.68mS ?

    or am i approaching this completely wrong?

    thanks for reading !
     
  2. beenthere

    Retired Moderator

    Apr 20, 2004
    15,815
    282
    At 60 Hz, one cycle takes 16.67 ms. That is 46.3 us/degree.
     
  3. Cabwood

    Member

    Feb 8, 2009
    20
    0
    Firstly, cos(2.pi.t) corresponds to a freqency of 1Hz, or period of 1s.
    Therefore, cos(120.pi.t) is 60 times greater in frequency, with a period of 1/60s.
    1.01 degrees represents 1.01/360 of a cycle's period.
    So, the output leads the input by 1.01 / (360 * 60) s.
     
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