# Help solving network analysis with a few loops

Discussion in 'Homework Help' started by dabulls2900, Feb 15, 2012.

1. ### dabulls2900 Thread Starter New Member

Feb 15, 2012
2
0
The question is: For I1 = 6 mA and I2 = 10 mA, determine the loop current IB in the circuit in mA; and here is a diagram- http://i40.tinypic.com/jj9pqa.png

Now what I did was calculate the total current*resistance in the loops and equaled them to 0 as so:

IA(2k) + IA(2k) + IA(1k) + IB(3k) + IC(1K) = 0 (i can plug in I1 and I2 and solve)

However I am not completely sure how to solve this out after. Am I taking the right steps? Thanks

2. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
783

Note that

IA=I1

and

I2+IB=I1+IC

To assist interpreting the circuit I would mark a convenient reference node - such as at the bottom of the I2 source.

3. ### steveb Senior Member

Jul 3, 2008
2,433
469
If Ia, Ib and Ic are mesh currents, should't it be I2+Ib=Ic ?

4. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
783
Yes - my mistake.

5. ### dabulls2900 Thread Starter New Member

Feb 15, 2012
2
0
thanks for all the help. i got it last night.