Help solving network analysis with a few loops

Discussion in 'Homework Help' started by dabulls2900, Feb 15, 2012.

  1. dabulls2900

    Thread Starter New Member

    Feb 15, 2012
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    0
    The question is: For I1 = 6 mA and I2 = 10 mA, determine the loop current IB in the circuit in mA; and here is a diagram- http://i40.tinypic.com/jj9pqa.png

    Now what I did was calculate the total current*resistance in the loops and equaled them to 0 as so:

    IA(2k) + IA(2k) + IA(1k) + IB(3k) + IC(1K) = 0 (i can plug in I1 and I2 and solve)

    However I am not completely sure how to solve this out after. Am I taking the right steps? Thanks
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    Your method is not correct.

    Note that

    IA=I1

    and

    I2+IB=I1+IC

    To assist interpreting the circuit I would mark a convenient reference node - such as at the bottom of the I2 source.
     
  3. steveb

    Senior Member

    Jul 3, 2008
    2,433
    469
    If Ia, Ib and Ic are mesh currents, should't it be I2+Ib=Ic ?
     
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    Yes - my mistake.
     
  5. dabulls2900

    Thread Starter New Member

    Feb 15, 2012
    2
    0
    thanks for all the help. i got it last night.
     
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