In a series circuit, if you have 2 light bulbs attached, and then one light bulb burns out, will the other light bulb remain lit?
I thought the answer would be yes, because the light bulb is still screwed in and the contact point is still making contact. I thought you would have to unscrew the light bulb to break the contact and make the other light bulb go out.
If this isn't accurate, does it have something to do with the filament wire in the light bulb being burnt out, thereby breaking the complete circuit?
I thought the answer would be yes, because the light bulb is still screwed in and the contact point is still making contact. I thought you would have to unscrew the light bulb to break the contact and make the other light bulb go out.
If this isn't accurate, does it have something to do with the filament wire in the light bulb being burnt out, thereby breaking the complete circuit?