Help please

Discussion in 'Homework Help' started by mattm, Aug 10, 2009.

  1. mattm

    Thread Starter Member

    Aug 5, 2009
    19
    0
    as far as the generator is concerned, in a series-resonant LC circuit(with no resistor), L and C can be replaced by a resistor with the same value of L x C?
     
  2. mattm

    Thread Starter Member

    Aug 5, 2009
    19
    0
    or can you just replace it with a peice of wire?
     
  3. veritas

    Active Member

    Feb 7, 2008
    167
    0
    You need L and C for the circuit to be resonant.
     
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    In part this is correct - at least at resonance in a series LC circuit the effective impedance becomes equivalent to a resistance. If L & C are ideal then the effective resistance would be zero at resonance. But just replacing L & C with a resistance does not give an equivalent circuit at all other frequencies. For instance, a series LC circuit will not pass continuous DC current, whereas a resistor will. At all other frequencies the impedance is reactive - increasingly inductive above resonance and increasingly capacitive below resonance.
     
  5. JoeJester

    AAC Fanatic!

    Apr 26, 2005
    3,373
    1,159
    the only time I've seen replacing a series resonant circuit (antenna) with a resistor is when you connect the transceiver up to a dummy load.
     
Loading...