Hello folks.
Okay,
Please look at the schematic I attached.
As you may see there, the battery was rated as 12 volts and the lamp was rated as 6 volts. Am I correct? And the circuit has a switch in positive line of the circuit which is off. Am I right?
So since the battery was rated as 12 volts and the lamp was rated as 6 volts, is there any possibility that the lamp will be broken even though the switch is off? I am guessing no.
Okay, the electrons flows in the negative side, so that electrons can flows even though there is no positive line as the electrons flows in the negative side. But I am guessing I am wrong since if I were remember negative line will not produce electrons if there is no positive line. Eh, I really don't know.
Please help me understand this.
Any help would be appreciated.
Your folk mate,
Lightfire
Okay,
Please look at the schematic I attached.
As you may see there, the battery was rated as 12 volts and the lamp was rated as 6 volts. Am I correct? And the circuit has a switch in positive line of the circuit which is off. Am I right?
So since the battery was rated as 12 volts and the lamp was rated as 6 volts, is there any possibility that the lamp will be broken even though the switch is off? I am guessing no.
Okay, the electrons flows in the negative side, so that electrons can flows even though there is no positive line as the electrons flows in the negative side. But I am guessing I am wrong since if I were remember negative line will not produce electrons if there is no positive line. Eh, I really don't know.
Please help me understand this.
Any help would be appreciated.
Your folk mate,
Lightfire
Attachments
-
6.2 KB Views: 43