I'm looking to you electronics experts to help me source a variable resistor. I've searched google, electronics wholesalers, and the like to no available. I'm from the US, but living in Australia right now, and the pickings are slim regarding full on electronics stores. I'm looking for a resistor with the following specs; 1X variable 0 to 1k ohm resistor 50VAC rated 0.05W or more. Pretty simple right? I want it to be like the one pictured below, I will have to do my own sealing/waterproofing as it will be used for automotive purposes. Any help? TIA Ω

 

There is a thread around here called "Where to buy voltage regulators in Australia." or something like that. I would check those places listed in that thread to see what is available to you.

That may also be listed as a trim pot rather than a variable resistor or even a standard pot.


Here is the thread I was speaking of:
http://forum.allaboutcircuits.com/showthread.php?t=38583

[ed]
This is the best I could do with the amount of time I felt I could put in:
http://parts.digikey.sg/1/1/31608-pot-1k-ohm-5w-conduct-plastic-308n1k.html
[/ed]

 

There is a thread around here called "Where to buy voltage regulators in Australia." or something like that. I would check those places listed in that thread to see what is available to you.

That may also be listed as a trim pot rather than a variable resistor or even a standard pot.


Here is the thread I was speaking of:
http://forum.allaboutcircuits.com/showthread.php?t=38583

[ed]
This is the best I could do with the amount of time I felt I could put in:
http://parts.digikey.sg/1/1/31608-pot-1k-ohm-5w-conduct-plastic-308n1k.html
[/ed]

Thanks mate! I finally found a place called Jaycar that stocked a linear pot with the correct specs. I've gone with a 10k Ω instead of a 1k Ω.

Can someone post some insight on wiring a regular pot w/ three tabs as a variable resistor? It's my understanding the resistance between tab 1 and 3 is the full resistance of the pot, the resistance between 1 and 2, and 2 and 3 would be the combined resistance of the pot. Meaning if between pins 1 and 2 I have 200 Ω, then between pins 2 and 3 I'd have 800 Ω. Is that logic correct?

I want to put this pot inline with a single wire, so I assume I just cut the wire, put one lead on pin 1, and the other on pin 2. Again, correct logic?

Thanks.

 

It's my understanding the resistance between tab 1 and 3 is the full resistance of the pot, the resistance between 1 and 2, and 2 and 3 would be the combined resistance of the pot. Meaning if between pins 1 and 2 I have 200 Ω, then between pins 2 and 3 I'd have 800 Ω. Is that logic correct?

I want to put this pot inline with a single wire, so I assume I just cut the wire, put one lead on pin 1, and the other on pin 2. Again, correct logic?

You are correct.