help in Series Circuit

Discussion in 'Homework Help' started by eng\emadrashad, Dec 17, 2009.

  1. eng\emadrashad

    Thread Starter New Member

    Dec 17, 2009
    2
    0
    plz help in this problem
    :confused:

    thanks.......
    :D
     
  2. Fraser_Integration

    Member

    Nov 28, 2009
    142
    5
    The first circuit is a series circuit. This means that all the elements have the same value for current. Work this out by using the resistance of R3 and the p.d. across it (all given in question) then use that current value and ohms law to work out the rest.
     
  3. dsp_redux

    Active Member

    Apr 11, 2009
    182
    5
    The only thing you have to know here is Ohm's Law.
    \Delta V = R I. The current I is the same in R1, R2 and R3. You have I = \frac{4V-(-4V)}{8\Omega} = 1A. Since I is the same on all the branch, R_1 = \frac{12V-4V}{1A} = 8\Omega and R_3 = \frac{-4V-(-8V)}{1A} = 4\Omega. Not more complicated than that.
     
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