help in boolean algebra

Discussion in 'Homework Help' started by ibaness, Jul 22, 2006.

  1. ibaness

    Thread Starter New Member

    Jul 22, 2006
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    i can't prove this one:

    AC + AB + BC' = AC + BC'

    is it easy? thanks for the help!
     
  2. windoze killa

    AAC Fanatic!

    Feb 23, 2006
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    It has been a real long time since I did boolean but first guess would be AB-0

    I am sure I will be corrected.
     
  3. ibaness

    Thread Starter New Member

    Jul 22, 2006
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    i dunno. i just need to simplify this one but i dont know what to do with AB..
    im only high school so i dont know this one. hehe..
     
  4. hgmjr

    Moderator

    Jan 28, 2005
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  5. Dave

    Retired Moderator

    Nov 17, 2003
    6,960
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    Likewise it is some time since I did Boolean algebra, but here is my approach to this:

    From equation (1) take out A as a common factor:

    A(C+B) + BC' (2)

    Now again from equation (1) take out B as a common factor:

    AC + B(A+C') (3)

    Equate (2) and (3):

    A(C+B) + BC' = AC + B(A+C')

    Where C = C+B and C' = A+C', i.e. C is independant of B and C' is independant of A

    Therefore:

    AC + AB + BC' = AC + BC'

    Dave
     
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