# help in boolean algebra

Discussion in 'Homework Help' started by ibaness, Jul 22, 2006.

1. ### ibaness Thread Starter New Member

Jul 22, 2006
2
0
i can't prove this one:

AC + AB + BC' = AC + BC'

is it easy? thanks for the help!

2. ### windoze killa AAC Fanatic!

Feb 23, 2006
605
24
It has been a real long time since I did boolean but first guess would be AB-0

I am sure I will be corrected.

3. ### ibaness Thread Starter New Member

Jul 22, 2006
2
0
i dunno. i just need to simplify this one but i dont know what to do with AB..
im only high school so i dont know this one. hehe..

Jan 28, 2005
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5. ### Dave Retired Moderator

Nov 17, 2003
6,960
145
Likewise it is some time since I did Boolean algebra, but here is my approach to this:

From equation (1) take out A as a common factor:

A(C+B) + BC' (2)

Now again from equation (1) take out B as a common factor:

AC + B(A+C') (3)

Equate (2) and (3):

A(C+B) + BC' = AC + B(A+C')

Where C = C+B and C' = A+C', i.e. C is independant of B and C' is independant of A

Therefore:

AC + AB + BC' = AC + BC'

Dave