I'm stuck on this problem where we need to determine the 3 dB bandwidth if the op amp is the LMP 2231 biased with a single dc power supply.
I figured that the GB = 130 Khz. and I derived K to be 2/3 using the equation Vout = Vin[ (40/(20+40)) * (1+ 20/20)]. But I have no idea if this is right. Am I supposed to use the equation GB = K*BW and solve for BW?
I figured that the GB = 130 Khz. and I derived K to be 2/3 using the equation Vout = Vin[ (40/(20+40)) * (1+ 20/20)]. But I have no idea if this is right. Am I supposed to use the equation GB = K*BW and solve for BW?
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