A lightbulb has a positive temperature coefficient - that is to say the filament resistance increases with temperature, and conversely a very low resistance when cold - that's why the turn on surge causes most bulbs to blow at the instant of switch on.I think there's no real difference using either an inrush limiting resistor or a lightbulb of enought wattage at the input, except of course that if there's a shortcircuit the lightbulb won't tend to be destroyed. Leave the variac out though.
By the mention of two transformers it seems your smps is a half bridge forward topology, maybe look for a basic diagram on that topology and compare it to your circuit so you can understand what's going on?
Just stating the facts - what you do with them is up to you.Come on, man, yeah, but it's not gonna be in a final design, it's just for a test in a probably shortcircuited board, plus the drop in a lightbulb of enough wattage, say 150w, 200w is negligible and well within the limits of the input voltage of a smps.
A 200w bulb draws about 1.6 amps at 120v, there would be more stress to the transistor from the instantaneous current from the input capacitor.Just stating the facts - what you do with them is up to you.
A series bulb might save the fuse, but may not save your expensive chopper transistor.
On the plus side, a bulb can prevent the vapourised PCB traces that often happen between the MOSFET punching through and the fuse letting go.
Its only half that current on our 220V system, the point is that with a cold filament at switch on, the bulb draws something like 10 or 12x its steady running current.A 200w bulb draws about 1.6 amps at 120v, there would be more stress to the transistor from the instantaneous current from the input capacitor.
I think the safest thing to do would be to take off the transistors and verify the proper switching of the driver ic and any possible shortcircuit in the primary side be it in the transformer itself, not likely, or if it really is a half bridge, the capacitor on the other leg of the primary.
That sounds good, but the reality is that the driver IC probably requires feedback from the output to keep oscillating and running normally....
I think the safest thing to do would be to take off the transistors and verify the proper switching of the driver ic and any possible shortcircuit in the primary side be it in the transformer itself, not likely, or if it really is a half bridge, the capacitor on the other leg of the primary.
If you mean the bias voltage you can use a 10k 3w resistor (at 120v) from v+ and a zener to provide the vcc, it will oscillate. Also you can use this scheme to make the output of an smps vary from optocoupler-diode-drop voltage to full rated voltage. Not very wise for a permanent design, but funThat sounds good, but the reality is that the driver IC probably requires feedback from the output to keep oscillating and running normally.
So disconnecting the mains switching transistors and watching the oscillator was a technique that worked ok in the good ol' days but these days it will almost certainly leave you with a non functional oscillator.
Did you try a slow blow 0.5A or slightly larger fuse? Maybe try a 1A slow blow type. I suggested 0.5A as you said "a small SMPS".
Some photos of the SMPS might help a lot at this point! You've got access to expert fixers but are just spoon feeding us little bits of information at a time.
Photos and info on what you replaced and why, would be the next step.
Buddy, stop plugging the circuit as it is right now, there's a short circuit somewhere in the board and you need to find out where, if you put a larger fuse it's probably not gonna spare your transistors.Am I OK uploading a photo or two here...? I didn't know that...
Cheers, I'll try a larger fuse as well. But I wouldn't like to destroy the new transistors I fitted..!
Tom
All the SMPSU chips I can think of have an oscillator as a distinct functional block, they should try to carry on as normal with the chopper transistor missing - but the chip will think its not producing enough output, and will max the mark space ratio in an attempt to compensate.That sounds good, but the reality is that the driver IC probably requires feedback from the output to keep oscillating and running normally.