I need help finding the radius of equilateral triangle circumscribed circle.
I found the height of the triangle which is: \(h=\frac{\sqrt{3}}{2}a\)
Using Heron's formula or the simple formula \(A=\frac{bh}{2}\) I found the area of the equilateral triangle: \(A=\frac{a^{2}\sqrt{3}}{4}\)
But I need to find the circumference of the circumscribed circle, and to do that I need to know the radius of the circle.
I found the solution but I need to know how to come to that solution \((r=\frac{a}{\sqrt{3}})\).
I found the height of the triangle which is: \(h=\frac{\sqrt{3}}{2}a\)
Using Heron's formula or the simple formula \(A=\frac{bh}{2}\) I found the area of the equilateral triangle: \(A=\frac{a^{2}\sqrt{3}}{4}\)
But I need to find the circumference of the circumscribed circle, and to do that I need to know the radius of the circle.
I found the solution but I need to know how to come to that solution \((r=\frac{a}{\sqrt{3}})\).