Gate delays

Discussion in 'Homework Help' started by Fatima Rashd, Dec 27, 2015.

  1. Fatima Rashd

    Thread Starter New Member

    Dec 27, 2015
    4
    1
    Assume that tpd is the average of tPHL and tPLH. Find the delay from each input to the output in the circuit shown below by

    (a) Finding tPHL and tPLH for each path, assuming tPHL = 0.20 ns and tPLH = 0.36 ns for each gate. From these values, find tpd for each path.

    (b) Using tpd = 0.28 ns for each gate.

    (c) Compare your answers from parts (a) and (b) and discuss any differences.
    The answer is given as:
    tPHL-C,D to F = 2 tPLH + 2tPHL = 2(0.36) + 2(0.20) = 1.12 ns
    tPLH-C,D to F = 2tPHL + 2tPLH = 2(0.20) + 2(0.36) = 1.12 ns.
    Please anyone explain the answer.Thank You.
     
  2. WBahn

    Moderator

    Mar 31, 2012
    17,748
    4,796
    So how about:

    1) Showing the circuit that this problem is about (the crystal balls we all got for Christmas are still charging).
    2) Showing YOUR best attempt at an answer for each part.
     
  3. Fatima Rashd

    Thread Starter New Member

    Dec 27, 2015
    4
    1
  4. Fatima Rashd

    Thread Starter New Member

    Dec 27, 2015
    4
    1
    Extremely sorry.I was trying to understand the answer for 3 hours and tired after exhaust searching that's why such a stupid mistake I did.
     
    sailorjoe likes this.
  5. WBahn

    Moderator

    Mar 31, 2012
    17,748
    4,796
    Don't worry about trying to understand the answer.

    Forget that you have access to the answer.

    Take YOUR best shot at answering the question as best you can. Be sure to include your reasoning. That way we can see what you are thinking and where you might be going wrong.
     
    sailorjoe likes this.
  6. WBahn

    Moderator

    Mar 31, 2012
    17,748
    4,796
    It might help if you first described what t_PHL and t_PLH are. In doing so you might get some insight as to what conditions have to apply in order for the propagation delay from the C or D input to the F output to even be meaningful.
     
    sailorjoe likes this.
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