On the x-coordinate, there is straight line AB, point A is fixed on the x-coordinate, point B is located at any point x-coordinates, to describe this function ?
The point slope form is: (y - y0) = m(x - x0) (x0, y0) are the coordinates of one of the points if (x1, y1) are the coordinates of another point then m = (y1 - y0) / (x1 - x0)
You only talk about the x-coordinate. Are you working with a function in an x-y plane, or just on a number line? A picture would really help. As I try to interpret this, it only makes sense if it is reworded as: On the x-y plane a function is described by a straight line AB. The point A is fixed at coordinate <x0,y0>, The point B is located at an arbitrary point, <x1,y1>, What is the function, y=f(x), that describes this function. Does that sound close to what you are being asked for? If so, then is the function supposed to match only the portion of the line between A and B, or the entire line that passes through A and B?
x-coordinate represents there is no need for labeling (x1,y1) plane represents function can be solved in the x-coordinate ( indicated in red letters ) , , AB=function ? label (x.) - takes place in the x-coordinate
There's no red letters in your post, so I'm not sure what you were trying to indicate with them. I think I am following what you are doing. I'm not too comfortable with the math set-theoretic notation, so I may not be following you completely. If I am, then you are basically saying that you looking for a function f(x) such that f(x_a) = A, f(x_x) = B, and the f(x) is linear. Is that correct? Also, you need to provide YOUR best attempt to solve YOUR homework. Not only is that expected, but it goes a long way toward making sure that we are on the same page.
There are two cases: 1) Any two given points that lie on the line. 2) The slope and a point on the line. Post #3 is your solution.
- place (label for x-coordinate) Mathematics official says geometric objects measures must be positive numbers, say my function to geometric objects measures may be negative numbers question - how to make it look proceedings graphics of my functions in the plane (Cartesian coordinate system)?
Well your mathematics teacher is wrong. Zero is a valid value. Zero is neither negative nor positive. He or she may want non-negative values, but that is not the same as positive definite. So your modulus function will do this alternatively you might like to know that we often use this one instead since the modulus function is not differentiable at x=0. but this one is.[/quote]
The mapping function from the x-coordinates of the plane (Cartesian coordinate system) y = x-a, x and a remain on the x-coordinate, y goes to the y-coordinate. view photo https://pkxnqg.bn1302.livefilestore...WSh5idkVdC-swrTkqYaXV8fmts9x7Ks/ii.png?psid=1 the lines of x and a parallel to the y-coordinates line of y parallel to the x-coordinate formed at the intersection of real points A and B points A and B are combined and gets straight line AB is given by x = 4, a = 2, y = 2 Repeat for x = 3.5, a = 2, y = 1.5, view photo formed at the intersection of real points C and D points C and D are combined and received straight line CD https://befwwg.bn1302.livefilestore...DKraCcJKIy-UHkR4VeCHL_PmPvJTSMeM/i.png?psid=1 connect the dots AC (BD) straight lines AB and CD ABDC points form the surface of 4≥x≥3.5 Draw a graph of the function at the current proceedings for a) y=|a-x| b) y=-|a-x| c) y=a-x d) y=x-a e) y={|a-x|}{-|a-x|}
y=|2-x| graph, the red surface https://cfxpzq.bn1302.livefilestore...duf35TDz7kJFlvpinPGfiGmOhMAVbDw/01.png?psid=1 b) y=-|2-x| graph, the red surface https://nq6hfq.bn1302.livefilestore...xhUjRvcF6i6WXHS-qNoA1O50MwSx-Kw/02.png?psid=1 c) y=2-x graph, the red surface https://0nivia.bn1302.livefilestore...qqqkUyEXwbMEkel843ZQ20Rq__x6V-A/03.png?psid=1 d) y=x-2 graph, the red surface https://d6pekg.bn1302.livefilestore...0AJlHabqjfVBAgiGORjpymT7vzmMKCA/04.png?psid=1 e) y={|2-x|}{-|2-x|} graph, the red surface https://qhdsnq.bn1302.livefilestore...HeXxWALY-BwcLW4G5ObhnQSYfKmEaVQ/05.png?psid=1 which are geometric objects obtained for valuesx and y , shape a≥x≥b ( a≥y≥b ) ? , you have a graph
a) b), the same graph is reversed only to , and relates to a negative value y the scene ()x-coordinates , ()y-coordinates ,( )plane Graph functions , mapped straight line 2≥y≥0 ( The general form b≥y≥0 , b>0 ) rectangular isosceles triangle https://2bl1tq.bn1302.livefilestore...kPva7zBN1RUVuKqNL12VYCgSDrGVr0A/y1.png?psid=1 3≥y≥1 ( The general form c≥y≥b , b>0 , c>0 ) regular trapeze https://dc4d8a.bn1302.livefilestore...WL9PS8DTbYrpR0fD2Vhx9lCacxIjf8g/y2.png?psid=1 1≥x≥-1 ( The general form c≥x≥b x<a , c≥x≥b x>a ) rectangular trapeze https://o9amca.bn1302.livefilestore...FCWt4FDy7sqTIZNX57SWFbuE4v6HR6w/y3.png?psid=1 6≥x≥-1 ( The general form c≥x≥b , b>a , c<a , |b||c|) pentagon https://pkxoqg.bn1302.livefilestore...ThLPbQyTNzHDTKaz5o26xnOhTE2PD9Q/y4.png?psid=1 more geometric objects that can be obtained ???
Operations on sets - difference, this operation returns a new geometric objects { 5≥ x ≥0 } {1≥y≥0} , hexagon https://nq6ifq.bn1302.livefilestore...qgLXrV5A5-e_o-SITTtYzhwpKXd4QiQ/a1.png?psid=1 { 3≥y≥0}{1≥x≥0} heptagon https://0niwia.bn1302.livefilestore...XOyUtFLLOTWA8tFqTLypALME92OR_Jw/a2.png?psid=1 {5≥x≥-1}{2≥y≥1} trapezoid and triangle together https://d6pfkg.bn1302.livefilestore...pSGGWByH1jMIRAA6Q1VUZ2sP6cr8U0Q/a3.png?psid=1
I remember socratus used to post threads in this fashion, until no one bothered to read or answer them any more.
The symmetry of geometric object trapez - https://dc4e8a.bn1302.livefilestore...INtxRZAQz1QXkFp5aRMZDT3JqsHa5w/aa1.png?psid=1 to make it look a graph
Ah, yes. That was the socratus that associated themselves, rather appropriately, with a particularly dense metal, right? You lasted longer than I did.