Hey guys.
I think my answer sheet is mistaken...
I have the following problem:
Half wave rectifier, with 47μF filter and 10k load. RMS on primary xformer winding is 120v at 60Hz. Transformer ratio is 8/1. Find Vdc and Vr. (Avergae voltage and ripple voltage)
120*√2 = 169.705v on the primary winding peak
169.705 / 8 = 21.21v on the secondary winding peak
So since it's a half wave rectifier,
21.21 / ∏ = 6.75v is the average voltage (Vdc)
And finally,
Vr = 6.75 / (60Hz * 10KΩ * 47μF) = 239.36mv
Now my answer sheet says that it should be 752.13mv
It would seem that they used Vp / (∫*Ω*f), whereas I used Vdc / (∫*Ω*f). I strongly believe that to be incorrect, because using Vp instead of Vdc does NOT take into account that it is running on a HALF wave rectifier... Which effectively doubles the time it takes for the capacitor to start charging again.
Thanks guys!
I think my answer sheet is mistaken...
I have the following problem:
Half wave rectifier, with 47μF filter and 10k load. RMS on primary xformer winding is 120v at 60Hz. Transformer ratio is 8/1. Find Vdc and Vr. (Avergae voltage and ripple voltage)
120*√2 = 169.705v on the primary winding peak
169.705 / 8 = 21.21v on the secondary winding peak
So since it's a half wave rectifier,
21.21 / ∏ = 6.75v is the average voltage (Vdc)
And finally,
Vr = 6.75 / (60Hz * 10KΩ * 47μF) = 239.36mv
Now my answer sheet says that it should be 752.13mv
It would seem that they used Vp / (∫*Ω*f), whereas I used Vdc / (∫*Ω*f). I strongly believe that to be incorrect, because using Vp instead of Vdc does NOT take into account that it is running on a HALF wave rectifier... Which effectively doubles the time it takes for the capacitor to start charging again.
Thanks guys!