full adder carry implementation using one multiplier and take each data as 8 bit

Discussion in 'Programmer's Corner' started by satyabratasahoo89, Jul 20, 2012.

  1. satyabratasahoo89

    Thread Starter New Member

    Jul 20, 2012
    1
    0
    please friend answer

    given cout=ab + bc + ca where a,b,c are input and each of 8bit

    implement cout using 1 multiplier in VHDL
     
  2. WBahn

    Moderator

    Mar 31, 2012
    17,757
    4,800
    Okay. So what have you done so far on this?

    What, if any, other constraints do you have to abide by? For instance, can this be a sequential solution or does it have to be combinatorial only?
     
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