Frequency response 1st order

Discussion in 'Homework Help' started by Montop, Nov 13, 2015.

  1. Montop

    Thread Starter New Member

    Oct 29, 2015
    3
    0
    [​IMG]

    I am having a bit of trouble trying to figure this out. The equation I come up with keeps canceling Omega out.

    Attempt:

    Converting the circuit to the frequency domain the capacitor becomes  \frac{4}{j \omega} .

    I then used a current divider to find  \underline Y(j \omega) = \underline u(j \omega) * \frac{(2+(\frac{4}{j \omega}))}{6+(2+(\frac{4}{j \omega}))}

    Simplifying this I get the frequency response to be  \frac{1}{2} . I am fairly certain that his is not correct.
     
  2. RBR1317

    Active Member

    Nov 13, 2010
    227
    47
    I would tend to agree since Y=U*Z, where Z is the parallel combination of the R & RC branches.
     
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