fourier coefficients of a square wave

Discussion in 'Homework Help' started by jstrike21, Feb 3, 2010.

  1. jstrike21

    Thread Starter Member

    Sep 24, 2009
    104
    0
    I was given fundamental period Fo=4s so this means Wo=pi/2.
    Then , x(t)={1, 0<t<2 and 2, 2<t<4
    x(t) is periodic.
    I plotted the sine wave now i have to write the formula for the fourier coefficients Ak and compute A0, A1, and A2.

    Im not sure how to get a formula for x(t).
    help please
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    For the interval of integration t=0 to 2

    x(t)= 1


    For the interval of integration t=2 to 4

    x(t)= 2
     
  3. jstrike21

    Thread Starter Member

    Sep 24, 2009
    104
    0
    wow I'm going to go crawl in a hole and not show my face again:D
     
  4. jstrike21

    Thread Starter Member

    Sep 24, 2009
    104
    0
    I have Ak= 1/To* Integral from 0 to 2(e^(-jwt)dt)
    I forgot how to solve this integral can anyone help?
     
  5. GirishC

    Active Member

    Jan 23, 2009
    58
    0
    ak = (1/T0) <0> I <2> e^-jwt dt
    = (1/T0)* [(1/-jw)* e^-jwt] <0> to <2>
    = (1/-jwT0) [e^0 + e^-2jw]

    and you can solve further to get cosine and sine terms
     
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