formula for parallel circuits

Discussion in 'General Electronics Chat' started by Michele, Nov 29, 2005.

  1. Michele

    Thread Starter New Member

    Nov 29, 2005
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    If the total circuit dissipation is 1.44 Watts on a three branch parallel resistor and branch 1 is half the current value of branch 2 and one third the current value of branch 3; v applied to the circuit is 120V.
    What are the v, i, r, and p values for the circuit and for each branch
     
  2. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    Total R of the circuit is V^2/R = (120*120)/1.44 or 10,000 ohms

    Total I of the circuit is V/R = 120/10000 = 0.012 Amps

    These are the starting points. Everything else proceeds from these values.

    hgmjr
     
  3. JoeJester

    AAC Fanatic!

    Apr 26, 2005
    3,268
    1,063
    Michelle,

    Draw your circuit and get into the habit of constructing a table like the one I attached illustrating for your problem.

    Fill in the knowns and think about the problem.
     
  4. HEALEY

    New Member

    Nov 10, 2004
    5
    0
    [attachmentid=995]

    HOPE THE ATTACHMENT HELPS - CHECK LIBRARY FOR ELECT ENGRG BOOK WITH KIRCHOFF'S LAWS
    SHOULD EXPLAIN MY LOGIC IN ATTACHMENT[attachmentid=995]
     
  5. HEALEY

    New Member

    Nov 10, 2004
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    Sorry- there is an incorrect value in the attacment I transmitted earlier - new attachment adds a comment with the correct value
     
  6. HEALEY

    New Member

    Nov 10, 2004
    5
    0


    Again my apologies - comment did not appear - try this one
     
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