formula for parallel circuits

Discussion in 'General Electronics Chat' started by Michele, Nov 29, 2005.

1. Michele Thread Starter New Member

Nov 29, 2005
1
0
If the total circuit dissipation is 1.44 Watts on a three branch parallel resistor and branch 1 is half the current value of branch 2 and one third the current value of branch 3; v applied to the circuit is 120V.
What are the v, i, r, and p values for the circuit and for each branch

2. hgmjr Moderator

Jan 28, 2005
9,030
214
Total R of the circuit is V^2/R = (120*120)/1.44 or 10,000 ohms

Total I of the circuit is V/R = 120/10000 = 0.012 Amps

These are the starting points. Everything else proceeds from these values.

hgmjr

3. JoeJester AAC Fanatic!

Apr 26, 2005
3,393
1,211
Michelle,

Draw your circuit and get into the habit of constructing a table like the one I attached illustrating for your problem.

Fill in the knowns and think about the problem.

4. HEALEY New Member

Nov 10, 2004
5
0
[attachmentid=995]

HOPE THE ATTACHMENT HELPS - CHECK LIBRARY FOR ELECT ENGRG BOOK WITH KIRCHOFF'S LAWS
SHOULD EXPLAIN MY LOGIC IN ATTACHMENT[attachmentid=995]

5. HEALEY New Member

Nov 10, 2004
5
0

Sorry- there is an incorrect value in the attacment I transmitted earlier - new attachment adds a comment with the correct value

6. HEALEY New Member

Nov 10, 2004
5
0

Again my apologies - comment did not appear - try this one