Finding values

Thread Starter

Robin Mitchell

Joined Oct 25, 2009
819
Hi everyone,

Having a few problems



Uploaded with ImageShack.us

Lets say we have the circuit above, how do i find suitable values for the resistors? (9V supply)

Do i start by deciding what currents i have in different areas and the voltages and then choose resistor values that give those. And which bits can i treat seperatly?

Thanks :)
 

Jony130

Joined Feb 17, 2009
5,488
You don't need any resistor in series with gate (AND).
And resistor in base of the BJT is also unnecessary. Honestly you don't need this whole circuit. Simply connect LED + resistor to power supply.
 

Thread Starter

Robin Mitchell

Joined Oct 25, 2009
819
it was just an example, obviously i would never use this circuit. But what i want to do was just find values.

So lets say i want 13mA going in and out. Determine what current i want in the different wires, then select resistors so that it works....is that how you do it?
 

Audioguru

Joined Dec 20, 2007
11,248
Only the transistor has any current. Its collector to emitter has the current for the LED and its current-limiting resistor. Its base has up to 1/10th the collector current.

The inputs of the gate do not have any current (Cmos gate) so its input resistors are not needed and its output current is the low current to the base of the transistor so the gate's output resistor is not needed.

So the only thing to be calculated is the calue of the resistor that limits the current of the LED.
 

Wendy

Joined Mar 24, 2008
23,429
Many times it doesn't matter, a wide range of resistors will work fine. In that case I lean towards the higher resistances for power efficiency. Other times the constraints are rigid, like with powering an LED. You need to be able to pick between the two.

That schematic the base resistor might be needed on other configurations. I answered a question two days ago on exactly that issue. The resistors on the gate inputs are not needed. AG has just explained how the base resistance might be selected.



While this is an OR gate the principle is the same. Rotate the diodes 180° and it is a AND gate.
 

Wendy

Joined Mar 24, 2008
23,429
CMOS is a highly efficient logic family. Their typical current draw while in a static mode is in the µA, sometime in the picoAMP range. Only when they are switching do they draw current in any quantity. Besides their wide voltage range this is another reason they are so popular.

Modern CPUs use CMOS, but they have billions of transistors and switch extremely fast.
 
Top