Hey everyone, my problem is finding the stationary point of the function:
\(f(x,y) = (x+y)exp(x^2-y)\)
By differentiating f WRT x i obtained the answer:
\(\frac{df}{dx} = exp(x^2-y)[2x^2+2xy+1] = 0\) (1)
and differentiating f WRT y I got:
\(\frac{df}{dy} = exp(x^2-y)[1-x-y]\) (2)
I could be wrong with my answer because I am now stuck because I always have one equation that is a function of two variables (x and y). However, I have tried three times and arrive at the same solution for both. Please help!
Thanks!!
\(f(x,y) = (x+y)exp(x^2-y)\)
By differentiating f WRT x i obtained the answer:
\(\frac{df}{dx} = exp(x^2-y)[2x^2+2xy+1] = 0\) (1)
and differentiating f WRT y I got:
\(\frac{df}{dy} = exp(x^2-y)[1-x-y]\) (2)
I could be wrong with my answer because I am now stuck because I always have one equation that is a function of two variables (x and y). However, I have tried three times and arrive at the same solution for both. Please help!
Thanks!!