hey

i would like to as a question about some kind of issue about finding the value "x" that is shown the fig below , well the value of the Freq. should be 96Khz which is the value i need to reach and this is by passing some stages to reach only the value of the freq. =96Khz (thats mean removing all the previous Freq. and voltages and only keeping the last value of Freq =96Khz in order to have the analogue graph . so i'll post what stages i must pass in order to reach that point that iv tried but still can't figure out . if someone know plz help as soon as u can .

here is the pic of the circuit that i attached in the post for those who can help me

and the stages that must pass through this circuit must look like that

 

Your post makes no sense to me.

 

Actually, it makes sense to me.

You have 4 signals being summed:
50Hz 220v
10kHz, 10v
20KHz, 5v
X kHz, 10v
One way to approach it would be to use three very narrow band-reject filters in series; one for 50Hz, one for 10kHz, and one for 20kHz.
Another way would be to subtract the known frequencies in subsequent sum modules, eg: instead of summing the signal with 50Hz 220v the second time, sum it with 50Hz -220v, which should be 180º out of phase with the original 50Hz 220v.

Oops, OK, I posted without really looking at the 2nd part of the question very hard.

The 1st high-pass filter can get rid of most of the low-frequency stuff.

I don't know what you mean by a high-pass filter with same frequency carrier. Are you trying to say an IF section?

An LC tank acts as an open circuit to it's resonant frequency, and as a short to ground to frequencies other than resonant.

I guess this is homework, but you don't know where to start, right?

 

Actually, it makes sense to me.

One of the things that confused me was the title.