Finding Currents for 3 PH unbalanced Wye load

Discussion in 'Homework Help' started by salim_9292, Mar 7, 2010.

  1. salim_9292

    Thread Starter New Member

    Mar 6, 2010
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    An unbalanced wye load consists of a 4 + j3 Ohm impedance connected to phase A, a 3 + j3 Ohm impedance connected to phase B, and a 4 + j5 Ohm impedance connected to phase C. The sequence is ABC with VAB = 208 volt at an angle of 0°. Assuming all currents are flowing from the source to the load, calculate the value of the followings in Polar values:
    a. I(A) [where I(A) is the phase A current].
    b. I(B) [where I(B) is the phase B current].
    c. I(C) [where I(C) is the phase C current].
    d. I(N) [where I(N) is the phase N current].

    Great Thanks,
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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