Find the cut-off frequency

Thread Starter

basim

Joined May 12, 2009
1
the question is
From you result in table Find the cut-off frequency


circuit figure



lab result


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thanks so much in advance
 

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A cutoff frequency is often defined as the point where the gain of the filter/amplifier is down 3 dB. Is that how it is defined in your class?

Are there any points in your table that meet that criterion?
 

Ron H

Joined Apr 14, 2005
7,063
If those are lab results, you should have started your input at a lower frequency, and ended at a higher frequency.
 

BrianH

Joined Mar 21, 2007
43
Hi Ron.H;

Since there are no bandwidth limiting components placed in that circuit, surely the cut-off will not occur until the input frequency is increased high enough to start the miller effect?

So, with that in mind, I will agree that he should have taken measurements at a much higher frequency but I'd suggest 20Hz was a more than adequate starting point?

Brian.
 
A capacitor is typically placed between the source and the input to remove the DC component of the source. Same goes for the output. So, looking at the circuit, there is reason to believe that there is something going to happen at the low end of the spectrum. The data also begins to show the falling off of the gain.

I would suggest starting your input at a lower frequency and ending at a higher frequency as Ron H suggested.
 

Ron H

Joined Apr 14, 2005
7,063
Hi Ron.H;

Since there are no bandwidth limiting components placed in that circuit, surely the cut-off will not occur until the input frequency is increased high enough to start the miller effect?

So, with that in mind, I will agree that he should have taken measurements at a much higher frequency but I'd suggest 20Hz was a more than adequate starting point?

Brian.
Well, the emitter bybass cap and resistors should set the low end corner at around 20Hz, but his data shows that the response was almost flat at that frequency. The results imply that the cap value is closer to 250uF, rather than 100uF.
As for the high end, if the source impedance were really zero, Miller capacitance would not be a factor. A real-world generator is likely to have 50Ω or 600Ω output resistance, so the Miller effect will be present. In simulation, 500Ω matches his midband gain pretty closely. A 10pF scope probe will lower the high end corner frequency considerably.
 

PRS

Joined Aug 24, 2008
989
Basim, you obviously messed up, but you need to correct it -- for your own sake. There should be an hour that gives you access to a scope at school. Here's something I found out only in my last year at the university: The physics department would let you have anything you needed, like checking out books at the library. I checked out a set of weights (accurate grams scale type), but I realized I could have had just about anything I wanted right there in my dorm room!
 
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