The result for this problem is: -12.5 Cos(2t-53.13°) A I've found : Zc=-5J Zl= J I(2)= -5/2 = -2,5 A over 2 ohm resistor Then I've found Vc+Vl+Vr(2ohm) = ((-5+1)*-2.5)-5 =-15V I found current through 1ohm resistor = -15V/1= -15 A So I have -15-(-2.5) = -12.5 A Is it correct my procedure? How can I find angle of 53.13° ?? Thanks
Thats about 0.31Hz, at that frequency the capacitor will have a reactance of 5.1 Meg ohms, the inductor will be 1 ohm, i dont think any current will flow in the series circuit.
Phasor contains magnitude and angle. I don't see where you are using phasors. That is why you don't have any way to find the angle.