Exchanging current for voltage

Discussion in 'The Projects Forum' started by rispodium, Mar 5, 2014.

  1. rispodium

    Thread Starter New Member

    Mar 5, 2014
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    Hi I have a battery that is 36v and 10a/h.
    I want to increase voltage quite a bit and don't need
    that many amps. I have bought a circuit for this in the
    past but cannot find one. Does anyone know where I
    can buy one? Or what they are called?
     
  2. bertus

    Administrator

    Apr 5, 2008
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    Hello,

    I think you are looking for a boost conveter.
    How high voltage do you need?

    Bertus
     
  3. rispodium

    Thread Starter New Member

    Mar 5, 2014
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    Hi Bertus,

    I would like up to 100 volts if possible

    Thanks
     
  4. bertus

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    Apr 5, 2008
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  5. rispodium

    Thread Starter New Member

    Mar 5, 2014
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    Thanks Bertus.

    Thats basically what i want yeah. I will be using the battery to power
    a few normal plug in machines. I looked on one machine then and it said 500 va. what is this in watts? 500 watts?
     
  6. #12

    Expert

    Nov 30, 2010
    16,305
    6,814
    yeahbut...it's going to last about 30 minutes on that battery.
    Hope that's enough for you.
     
  7. bertus

    Administrator

    Apr 5, 2008
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    Hello,

    What kind of machines are you talking about?
    The given schematics will produce DC voltage.
    If you want AC voltage look at so called inverters.

    Bertus
     
  8. rispodium

    Thread Starter New Member

    Mar 5, 2014
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    Hi Bertus,

    I am talking about a vacuum system and and few things attached to it. made by oerlikon.
    I have tried to adjust the timezone and it is a UK one but for some reason its not showing.
    Do you know any of the formulas for working out power and time options from a battery?
    ie: more power for less time or more on time but with less power ?

    This would be very helpful.

    Thanks,

    From Dave
     
  9. bertus

    Administrator

    Apr 5, 2008
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  10. rispodium

    Thread Starter New Member

    Mar 5, 2014
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    Hi,

    oerlikon turbolab 80, but there will be some other components attached.

    Is there any formulas to work out how much power will be used and how quickly?
    and how much voltage and amps can be exchanged?


    thanks
     
  11. wayneh

    Expert

    Sep 9, 2010
    12,137
    3,054
    Power (in watts, instantaneous) is voltage times amps. Total energy (watt-hours) is power times time.

    For batteries, it's common to use amp-hours to quote capacity. If voltage is constant, multiplying by the nominal voltage gives you the energy content. That's not quite right because the voltage sags over time, but it's often close enough.
     
  12. bertus

    Administrator

    Apr 5, 2008
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    Hello,

    Looking at the datasheet, the turbolab 80 needs 88 to 264 AC (50/60 Hz). with a max power of 300 Watts.
    For this you can use an inverter that creates this voltage at 50-60 Hz.
    I assume it has a built-in switched mode powersupply that makes 24 Volts for the pump, as stated in the datasheet.
    The turbolab 80 contains a SL80 turbopump, wich uses 120 watts at startup and about 17 watts when at speed.
    The remaining power will probably be consumed by the rough pump.

    You could use an inverter like in this ebay add:
    http://www.ebay.co.uk/itm/500W-15-6...00948717899?pt=UK_Gadgets&hash=item2ec97a194b

    Bertus
     
    Last edited: Mar 7, 2014
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