even number counter design

Discussion in 'Homework Help' started by Xufyan, May 24, 2011.

  1. Xufyan

    Thread Starter Member

    Aug 3, 2010
    114
    0
    Hello,

    i have a problem designing a 4-bit even number counter.,
    the states of the counter is,


    0000 = 0
    0010 = 2
    0100 = 4
    1000 = 8

    in each number the LSB is '0'
    so when i draw the karnaugh Map of J0 is filled with 0s and K0 with 'X' (Don't Care) ?
    am i doing something wrong ??

    Edi: Problem solved !!
     
    Last edited: May 27, 2011
  2. RiJoRI

    Well-Known Member

    Aug 15, 2007
    536
    26
    "Edi: Problem solved !!"

    Care to share your solution for other seekers?

    My QnD (Quick & Dirty) solution would be to connect the counter output lines to the next highest input line:

    O0 -- I1
    O1 -- I2
    O2 -- I3
    O3 -- Not connected
    I0 is grounded.

    --Rich
     
  3. Xufyan

    Thread Starter Member

    Aug 3, 2010
    114
    0
    Jo is grounded
    and its really don't care either Ko is connected to Vcc or grounded because in both situations
    the output for the flip flop remains '0'.

    Jo=0(ground) , Ko=1 =>> Output = '0' (Reset)
    Jo=0(ground) , Ko=0 =>> Output = '0' (No change)

    Since Jo is grounded therefore there will be no situation where Output is equal to '1' ,
    it always remain 0.
     
    Last edited: May 27, 2011
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