Okay, I see the pattern you are talking about in iron, cobalt and nickel. I've got a huge excel file that lists all the elements and their spin. It won't let me upload an excel file and converted to pdf it is still way over 1 M byte so I can't upload it as a pdf file. It also won't let me upload it as a html file.It does give you spin. Just draw one box for each s, three boxes for each p and five for each d orbital. Then, as I said above, if you see 3d6, that means the 3d orbital has 6 electrons. Just fill in each of the five boxes with one electron (all in the same direction) and then add the sixth to any box in the other direction to make a pair.
the post I made about filling order, those orbitals in a single line (without a curve) can be grouped as one "valence shell". So, Iron's valence shell is made up of a 4s and 3p orbitals. 2 in s, 6 in p.
PS, this seems a lot like a homework question, should it be relocated?
Can I email it to you. My email is ...
It still doesn't really give me a clear answer. Other elements are ferromagnetic, as are various compounds and oddities like lithium gas at 1K.
Mn and Cr also have all those d shell electrons spinning in one direction but they are not ferromagnetic.
Elements in the neighborhood of 41 to 45 and 74 to 78 also have that d-shell with the same electron spins but they are not ferromagnetic. Gd and Dy (64 and 66) are listed as ferromagnetic but lack this characteristic spin.
Thank you very much for your time on this.
No, not homework. Retirement. Trying to get a grasp on something I never made sense of.
Filling order must be my question. I will have to take some time to get a handle on this. Thank you.
It does give you spin. Just draw one box for each s, three boxes for each p and five for each d orbital. Then, as I said above, if you see 3d6, that means the 3d orbital has 6 electrons. Just fill in each of the five boxes with one electron (all in the same direction) and then add the sixth to any box in the other direction to make a pair.
the post I made about filling order, those orbitals in a single line (without a curve) can be grouped as one "valence shell". So, Iron's valence shell is made up of a 4s and 3p orbitals. 2 in s, 6 in p.
PS, this seems a lot like a homework question, should it be relocated?
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