What would each of the meters read if R4 was, say, 1 Ω and all of the others were, say, 1 kΩ?

AM4=12A
AM3=0.012A+12A=12.012A
AM2=12.012A+0.012A=12.024A
AM1=12.024A+0.012A=12.036A

 

Which, if any, of these results are somewhat similar to what the meters are showing in the problem?

Yes.

 

Ok ...which fault condition caused the readings you saw on the diagram?

I can't find.

 

What would each of the meters read if R2 was, say, 1 Ω and all of the others were, say, 1 kΩ?

AM4=0.012A
AM3=0.012A+12A=12.012A
AM2=12.012A+0.012A=12.024A
AM1=12.024A+0.012A=12.036A

@RRITESH KAKKAR

Please consider:

1) For purposes of the exercise, the indicators may be taken as exhibiting zero resistance...
2) Recall that that EMF is constant in a parallel circuit...
3) Recall the technique of calculating resistances in parallel?...

Best regards
HP

 

yes i have done that only.

 

yes i have done that only.

Then please show your work

 

What would each of the meters read if R1 was, say, 1 Ω and all of the others were, say, 1 kΩ?
What would each of the meters read if R2 was, say, 1 Ω and all of the others were, say, 1 kΩ?
What would each of the meters read if R3 was, say, 1 Ω and all of the others were, say, 1 kΩ?
What would each of the meters read if R4 was, say, 1 Ω and all of the others were, say, 1 kΩ?

Which, if any, of these results are somewhat similar to what the meters are showing in the problem?

This was the question where there is 1ohm the current will be 12Amps similar to this when 1K current will be
V=I*R
12/1k=12mA

 

Ok ...which fault condition caused the readings you saw on the diagram?

Yes.

You may wish to rethink your response -- that was not a 'yes or no' question...

 

This was the question where there is 1ohm the current will be 12Amps similar to this when 1K current will be
V=I*R
12/1k=12mA

The current capability of the power supply is irrelevant in the context of this exercise...

 

You may wish to rethink your response -- that was not a 'yes or no' question...

The circuit is working fine yes.

The current capability of the power supply is irrelevant in the context of this exercise...

So, what is wrong ?

 

What would each indicator show if the resistances of all four resistors = 1KΩ???

AM4=12mA
AM3=24mA
AM2=36mA
AM1=48mA

 

@RRITESH KAKKAR

My apologies! -- I misread @WBahn 's post --- (Spec. I 'missed' the fact that, in each of his questions, the value of one resistor was set to 1Ω)

 

AM4=12mA
AM3=24mA
AM2=36mA
AM1=48mA

Yes! That is correct assuming each resistance = 1KΩ - As I mistakenly asserted -- So, Score that as a correct reply!!!

 

So... Are you ready to solve the problem as stated?

 

yes.

 

AM4=3mA
AM3=4+3=7mA
AM2=6+4+3=13mA
AM1=12+6+4+3=21mA

 

yes.

Think about it -- If all the indicators are reading the same value what does that tell you?

 

the circuit is normal

 

AM4=3mA
AM3=4+3=7mA
AM2=6+4+3=13mA
AM1=12+6+4+3=21mA

These values are imprecise to such an extent that I cannot be certain you calculated them correctly --- Granting, however, that your values are 'close enough' (was the circuit working properly):

the circuit is normal

How do you reconcile that with the fact that all four indicators are reading 12 amperes?!?!

 

@RRITESH KAKKAR

Because I feel the question is 'lacking' in one regard - I offer this: For 'purity' sake - Assume the power supply is not merely specified at 12 Amperes but current limited to 12 Amperes. --- Given the forgoing, what component is at fault and what is its fault resistance?