Hello again,
Oh sorry, i must have been reading too fast or something.
Please follow me on this. I think i wrote everything correctly but you can go over it.
Let's put another small resistor in series with R in the bottom lead, call it Rs.
Let's also reverse the red arrow for a minute, so it is pointing down.
With conventional current flow we assume that positive charge is flowing, and
since the resistor draws current from the battery, the flow will be down through
both resistors, so we have positive charge entering the top of Rs so the top
must be positive and that makes the bottom negative.
The voltage measured across Rs will be positive with the plus meter lead on top
of Rs and the minus lead on the bottom of Rs. The meter reads a positive
voltage therefore the current is positive.
Now let's put the red arrow back to pointing upwards. The current doesnt actually
change, just the arrow, and since we still have current flowing down through both
resistors, we still see a positive voltage at the top of Rs and since the flow is
now opposite to the red arrow, we have to state Io as being negative as in the
actual drawing.
Now let's assume electron current flow, which goes from the most negative to the
most positive, and leave the red arrow as it appears in the drawing.
The current flows up through both resistors, and since it is negative charge
that enters the bottom of Rs resistor first, the bottom must be more negative
than the top, the meter reads a positive voltage again. This time however
the current is in the same direction as the arrow, and since it is negative
charge flowing we must conclude that the current Io is negative.
Note that to read the current directly with the volt meter across Rs we would
actually have to reverse the meter leads because Io is drawn pointing up.
Summary:
In the first case we had positive charge moving in the negative direction so
the current as shown by Io was negative.
In the second case we had negative charge moving in the positive direction,
so the current as shown by Io was negative.
Simplification:
Since we never changed anything we should expect similar results no matter
how we think about the charges, positive or negative, as the two systems
are compatible. And it is really the job of the physicist to figure out what is actually
happening inside the wire, ie wave theory.
Oh sorry, i must have been reading too fast or something.
Please follow me on this. I think i wrote everything correctly but you can go over it.
Let's put another small resistor in series with R in the bottom lead, call it Rs.
Let's also reverse the red arrow for a minute, so it is pointing down.
With conventional current flow we assume that positive charge is flowing, and
since the resistor draws current from the battery, the flow will be down through
both resistors, so we have positive charge entering the top of Rs so the top
must be positive and that makes the bottom negative.
The voltage measured across Rs will be positive with the plus meter lead on top
of Rs and the minus lead on the bottom of Rs. The meter reads a positive
voltage therefore the current is positive.
Now let's put the red arrow back to pointing upwards. The current doesnt actually
change, just the arrow, and since we still have current flowing down through both
resistors, we still see a positive voltage at the top of Rs and since the flow is
now opposite to the red arrow, we have to state Io as being negative as in the
actual drawing.
Now let's assume electron current flow, which goes from the most negative to the
most positive, and leave the red arrow as it appears in the drawing.
The current flows up through both resistors, and since it is negative charge
that enters the bottom of Rs resistor first, the bottom must be more negative
than the top, the meter reads a positive voltage again. This time however
the current is in the same direction as the arrow, and since it is negative
charge flowing we must conclude that the current Io is negative.
Note that to read the current directly with the volt meter across Rs we would
actually have to reverse the meter leads because Io is drawn pointing up.
Summary:
In the first case we had positive charge moving in the negative direction so
the current as shown by Io was negative.
In the second case we had negative charge moving in the positive direction,
so the current as shown by Io was negative.
Simplification:
Since we never changed anything we should expect similar results no matter
how we think about the charges, positive or negative, as the two systems
are compatible. And it is really the job of the physicist to figure out what is actually
happening inside the wire, ie wave theory.
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