DSP - DTFT properties

Discussion in 'Math' started by Dritech, May 2, 2015.

  1. Dritech

    Thread Starter Well-Known Member

    Sep 21, 2011
    756
    5
    Hi all,

    With reference to the pdf in the link below second slide.
    I can see that j[dX(e^jw)/dw] was taken from the DTFT property, but how was it changed to jd/dw[1/(1-e^-jw)] and than to [αe^-jw/(1-αe^-jw)] ??

    http://www2.units.it/ramponi/teaching/DSP/materiale/Ch3(2).pdf

    Any kind of help would be highly appreciated and sorry for my poor English.
     
  2. Dritech

    Thread Starter Well-Known Member

    Sep 21, 2011
    756
    5
    Also, in slide 3 third bullet it is mentioned that δ[n-1] = e^-jw , but the property states that it is equal to δ(w)e^-jwn (please see attached diagram).
    Is δ(w) not written down because it is an impulse, hence it is equal to 1? and in e^-jwn , n is not written down since it is equal to 1?

    Thanks in advance.
     
  3. Dritech

    Thread Starter Well-Known Member

    Sep 21, 2011
    756
    5
    Any help please?
     
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