Doubt on clamping circuit.

Discussion in 'General Electronics Chat' started by simpsonss, Aug 24, 2011.

  1. simpsonss

    Thread Starter Active Member

    Jul 8, 2008
    173
    0
    hi,

    I'm constructing the biased clamping circuitas below. From what I know, I would get a signal as the second diagram. But when I measure from the scope I get the different result which is different with the one I expected. Can anyone help me on this?

    the input signal is 38.4Vpp.
    the output signal is Vb= 8V which is as shown in the second diagram. what is expected is Vb = 5V.

    10.JPG

    11.JPG



    Thank you.
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    The diode forward drop will add to the resulting peak value. Also if your 5V battery has any appreciable internal resistance the peak value will be higher still. What are the actual components you are using? Diode type, etc?
     
  3. simpsonss

    Thread Starter Active Member

    Jul 8, 2008
    173
    0
    hi, thanks for the reply. 5V component is from a 5V output adapter. and i'm using 1N4002 for the diode.
     
  4. ErnieM

    AAC Fanatic!

    Apr 24, 2011
    7,392
    1,605
    1N4002 is a poor choice for this, it is best suited for slow speed/high current, such as a bridge rectifier. Instead try a nice small signal diode such as a 1N918 or a 1N4148.
     
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