Little Ghostman
- Joined Jan 1, 2014
- 305
Start with this book
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Series caps reduces the value - AFAIK that also applies to back to back electrolytics, unless you reverse clamp both caps with a diode.So the only reason they put the caps back to back was to get a larger value cap?
Dis we not have a quite long thread about this topic quite recent. I think it was a thread started by R!f@@ as part of a amplifier project. Can not just now find the thread.The answer is simple, polarized caps (such as electrolytic and tantalum) can handle DC only, not AC. When a circuit is biased it will present a DC offset to the capacitor, but as in all things this is not always true. Non-polarized electrolytic caps can handle AC, as in a audio signal. You can make two polarized caps into a non-polarized equivalent by putting them back to back as shown.
We did indeed, and the final verdict was the ancient wisdom was indeed correct. It is possible to make two polarized caps into one non-polarized one.Dis we not have a quite long thread about this topic quite recent. I think it was a thread started by R!f@@ as part of a amplifier project. Can not just now find the thread.
If they are individually rated for 16V, should I consider the new non-polarized one also rated for 16V?It is possible to make two polarized caps into one non-polarized one.
*I don't think so,Bill!The image problem is there truly is a correct way to show schematics. Signal goes in the right, exits on the left, as in this sample schematic.*
You are aware which is left is which is right arnt you?*I don't think so,Bill!
The circuit you show is a basic SMPS,.
The input is on the LEFT,& the output on the RIGHT.
Its customary in the UK to have the Input on the Left side of a diagram which drives the Output circuit on the right side of the diagram.You are aware which is left is which is right arnt you?
The hand you would put a wedding ring on is the left, so look again and explain how the input is on the left?
Its customary in the UK to have the Input on the Left side of a diagram which drives the Output circuit on the right side of the diagram.
Look at any circuit of an audio preamp and power amp.
ie: main signal flow from left to right. as 'vk6zgo' has correctly stated, on Bills circuit, the 555 on the left is the driver for the right side power output stage.
I took it to be an attempt as a portable power device, nothing to do with the service power?It is not logical to a beginner to try to drive a signal into the power line.
Not so much at 5.5/6MHz - but analogue TV is gone now!It is not logical to a beginner to try to drive a signal into the power line. At first glance, it's impossible because of the low impedance of the power system..
I took it to be an attempt as a portable power device, nothing to do with the service power?
But as a circuit it has a few limitations and flaws.
Max.
Yes, when you "assume",you make an ASS out of U & me!I see what your saying now, I took the right side to be the driving side. But I didnt understand what the circuit was, so assumed the right showed the mains being dropped to drive a 555 circuit. My apologize I got it completely wrong!