I'm a little bit confused about the Vd Vs. Temperature.
The Diode Equation : [1] Id=Is(e^(Vd*q/n*k*T)-1),
so => [2] Vd=[k*T*n*ln((Id/Is)+1)]/q
Lets :
n=1
k=1.38e-23
T(°k)=273+T(°c)
q=1.6e-19
Id=1mA
Is=1e-12A
Vd/T=86.25e-6*20.72=1.79e-3
Vd(at 25°c)=1.79e-3*(273+25)=0.5326V
Vd(at 26°c)=1.79e-3*(273+26)=0.5343V
so ΔVd=Vd(26°c)-Vd(25°c)=0.5343-0.5326=1.7mV
In the litterature and in all the world at high temperature the Diode Voltage shouled be -2mV/°c ! and i see "+".
why the Vd at 26°c is higher then Vd at 25°c?
In the formula i need to write "-", because "Electron Charge" (q) ?
where is my misteke?
someone have an articale or link that can explain in simple?
10X
The Diode Equation : [1] Id=Is(e^(Vd*q/n*k*T)-1),
so => [2] Vd=[k*T*n*ln((Id/Is)+1)]/q
Lets :
n=1
k=1.38e-23
T(°k)=273+T(°c)
q=1.6e-19
Id=1mA
Is=1e-12A
Vd/T=86.25e-6*20.72=1.79e-3
Vd(at 25°c)=1.79e-3*(273+25)=0.5326V
Vd(at 26°c)=1.79e-3*(273+26)=0.5343V
so ΔVd=Vd(26°c)-Vd(25°c)=0.5343-0.5326=1.7mV
In the litterature and in all the world at high temperature the Diode Voltage shouled be -2mV/°c ! and i see "+".
why the Vd at 26°c is higher then Vd at 25°c?
In the formula i need to write "-", because "Electron Charge" (q) ?
where is my misteke?
someone have an articale or link that can explain in simple?
10X