Diode forward drop circuit

Discussion in 'Homework Help' started by uofmx12, Sep 7, 2011.

  1. uofmx12

    Thread Starter Member

    Mar 8, 2011
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  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    Your answer looks fine.
     
  3. simpsonss

    Active Member

    Jul 8, 2008
    173
    0
    ur measurement looks find for me too. The calculation is as follow:

    Apply KVL:

    -10V + VR + 0.7 =0
    VR= 9.3V

    I= VR/R
    = 9.3V / 1K
    = 9.3mA
     
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