Different results with PNP and NPN, looking for explanation

Discussion in 'The Projects Forum' started by Nora, Feb 28, 2016.

  1. Nora

    Thread Starter New Member

    Jul 8, 2010
    2
    0
    Hi-
    I'm driving a piece of LCD glass, no backlight, which draws 0.1uA measured with multimeter.
    circuit (NPN.jpg) is attached. The input is a 5V PWM signal. The output at the collector is ground, no switching. +V is +12V, but I've tried higher voltages.
    When I use a PNP, same input, the output is the same PWM signal but at about 1V.
    Why isn't the PWM signal duplicating at the collector?

    The LCD glass must be the issue (I do not have a spec sheet), as using an LED gives a similar signal at collector as base.
    Thanks in advance.
     
    • NPN.jpg
      NPN.jpg
      File size:
      467 KB
      Views:
      14
  2. #12

    Expert

    Nov 30, 2010
    16,261
    6,768
    The diode is allowing unlimited current to the transistor. You probably destroyed the transistor.
     
  3. AnalogKid

    Distinguished Member

    Aug 1, 2013
    4,518
    1,247
    What is the purpose of the diode?
     
  4. Nora

    Thread Starter New Member

    Jul 8, 2010
    2
    0
    The diode isn't meant to be there and I just removed from drawing. It wasn't in these tests I ran.
     
  5. AnalogKid

    Distinguished Member

    Aug 1, 2013
    4,518
    1,247
    With such a high load impedance, there is nothing to pull up the collector when the transistor is turned off. Replace the LCD with a resistor, 1K to 10K to start, and see if that gets you an output waveform. Then reconnect the LCD while leaving the resistor in the circuit and see if the waveform changes.

    ak
     
  6. RichardO

    Well-Known Member

    May 4, 2013
    1,231
    382
    Your drawing says "LCD Glass". Is this just the glass or is there a controller as well?

    If it is just the glass, you need to drive it with ac, not DC. If you use DC, the LCD will fail fairly quickly from electroplating.

    If it is an LCD shutter then you can drive it with a square wave and 2 inverters or the Q and Q-bar of a flip-flop. Drive the LCD from 2 outputs that are 180 degrees out of phase from each other. Note that the equivalent DC offset to the LCD must be small -- on the order of 50 mV. This requires a square wave that is right at 50% duty cycle such as the output of a toggle flip-flop. Inverters such as a 74HC04 or 74HC14 or a 74HC74 flip-flop can be used.
     
Loading...