# determine v0

Discussion in 'Homework Help' started by qwerty321, Oct 22, 2008.

1. ### qwerty321 Thread Starter Member

Oct 22, 2008
14
0
hello!
i have the circuit below and i need to determine V0 by using two methods:

1)apply KCL at node a and invoke KVL and OHM's law
2)transforming the voltage source to an equivalent current source that is combined with the 4mA source.

Ok let us begin with the 1)

applying kcl at node a gives:

4+i1-i2=0
then what next?

thank you

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2. ### mik3 Senior Member

Feb 4, 2008
4,846
63
This wrong because not all the 4mA from the source flow through a due to the presence of R4. Transform this current source to a voltage source with a series resistor and then solve for node a.

3. ### qwerty321 Thread Starter Member

Oct 22, 2008
14
0
i do not understand..if i do that what is the kcl equation then?

4. ### mik3 Senior Member

Feb 4, 2008
4,846
63
It will be composed of the current through R1, the current through R2 and the current through R4 (after you make the current source-R4 combination to voltage source-R4 combination). I dont mention the signs because they depend on the direction you will put on the diagram.

5. ### hgmjr Moderator

Jan 28, 2005
9,030
214
What mik3 is attempting to get you to recognize is that the current source in parallel with the resistance in your circuit is the Norton's equivalent to a specific voltage and its series resistance. I have provided this link to the section in the AAC ebook that describes Norton's Theorem. Basically, all you need to do is convert the Norton's equivalent circuit into its voltage and resistance and then you will have a more recognizable circuit that you can then tackle with KVL or KCL.

hgmjr