# determine v0 #2

Discussion in 'Homework Help' started by qwerty321, Oct 25, 2008.

1. ### qwerty321 Thread Starter Member

Oct 22, 2008
14
0
Hello..well i have the figure above and i need to determine V0..
i am using source transformation but at the end,i am ending up with two variables (Io and VO)
so i think i need a way to get I0 but how?
and if i use the node voltage analysis i end up with the same thing
help pelase
thank you

File size:
4.5 KB
Views:
23
2. ### mik3 Senior Member

Feb 4, 2008
4,846
63
Just apply KCL to the two nodes at top of the circuit and solve the unknowns with simultaneous equations. Finally, Io equals I through R3

3. ### alwayslearning Member

Feb 27, 2008
22
0
I would suggest using thevenin; remove the 2 ohm load-find Rth.

Then use the superposition Theroem to find Vth; which will be in terms of a constant plus 3*Io.

Then attach your 2 ohm load and solve for Vo using the voltage divider princible.

Then Io=Vo/Ro=...

Solve for Io?

Finally Vo=Io*2 ohms

4. ### hgmjr Moderator

Jan 28, 2005
9,030
214
Greetings qwert123,

Have you been able to get any further along with your analysis of the problem you posted?

hgmjr

5. ### Ratch New Member

Mar 20, 2007
1,068
3
qwerty321,

Although we can get Io directly by node analysis, let's try something different. Like using a supermesh instead.

Designate the loop currents I1,I2, and I3 from left to right. Make a supermesh by mentally erasing the dependent current source, but remembering its effects. Then the equations of the two loops are:

24 -2*I1-2*I2 -4*(I2-I3) -12 = 0, and 12 -4*(I3-I2) -(2+2)*I3 = 0

And the equation for the dependent source, I1 -I2 = -3*I3

Three equations and three unknowns are solved to be I1,I2 and I3 = -9,9,and 6 respectively. So the dependent current source of 18 amps splits at the top with 9 amps going left, and 9 amps going right, and 6 amps going through R4.

Ratch

6. ### JoeJester AAC Fanatic!

Apr 26, 2005
3,316
1,109
Do you know R4 is shorted with a jumper in your diagram?