determine v0 #2

Discussion in 'Homework Help' started by qwerty321, Oct 25, 2008.

  1. qwerty321

    Thread Starter Member

    Oct 22, 2008
    14
    0
    Hello..well i have the figure above and i need to determine V0..
    i am using source transformation but at the end,i am ending up with two variables (Io and VO)
    so i think i need a way to get I0 but how?
    and if i use the node voltage analysis i end up with the same thing
    help pelase
    thank you
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    Just apply KCL to the two nodes at top of the circuit and solve the unknowns with simultaneous equations. Finally, Io equals I through R3
     
  3. alwayslearning

    Member

    Feb 27, 2008
    22
    0
    I would suggest using thevenin; remove the 2 ohm load-find Rth.

    Then use the superposition Theroem to find Vth; which will be in terms of a constant plus 3*Io.

    Then attach your 2 ohm load and solve for Vo using the voltage divider princible.

    Then Io=Vo/Ro=...

    Solve for Io?

    Finally Vo=Io*2 ohms
     
  4. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    Greetings qwert123,

    Have you been able to get any further along with your analysis of the problem you posted?

    hgmjr
     
  5. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    qwerty321,

    Although we can get Io directly by node analysis, let's try something different. Like using a supermesh instead.

    Designate the loop currents I1,I2, and I3 from left to right. Make a supermesh by mentally erasing the dependent current source, but remembering its effects. Then the equations of the two loops are:

    24 -2*I1-2*I2 -4*(I2-I3) -12 = 0, and 12 -4*(I3-I2) -(2+2)*I3 = 0

    And the equation for the dependent source, I1 -I2 = -3*I3

    Three equations and three unknowns are solved to be I1,I2 and I3 = -9,9,and 6 respectively. So the dependent current source of 18 amps splits at the top with 9 amps going left, and 9 amps going right, and 6 amps going through R4.

    Ratch
     
  6. JoeJester

    AAC Fanatic!

    Apr 26, 2005
    3,373
    1,159
    Do you know R4 is shorted with a jumper in your diagram?
     
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