Design a full-wave bridge rectifier circuit to deliver 10 volts dc with less than 0.1 volt (pp) ripple into a load drawing up to 10 mA. Choose the appropriate ac input voltage (by means of a transformer) assuming 0.6 volt diode drops. Be sure to use the correct ripple frequency in your calculation.
**See my attached diagram**
So far, i determined that my f=120 Hz, so I used the equation
dV=I/2Cf to solve for C=4.17E-4F
Next, I used Ohm's law to find the resistance: R=V/I=.6V/10E-3A=60 Ohms.
Since to get to the load we have 2 voltage drops of .6V, our DC from the transformer has to be 10+1.2=11.2V
I don't know how to solve for the input voltage without the number of turns . Any help would be great!
**See my attached diagram**
So far, i determined that my f=120 Hz, so I used the equation
dV=I/2Cf to solve for C=4.17E-4F
Next, I used Ohm's law to find the resistance: R=V/I=.6V/10E-3A=60 Ohms.
Since to get to the load we have 2 voltage drops of .6V, our DC from the transformer has to be 10+1.2=11.2V
I don't know how to solve for the input voltage without the number of turns . Any help would be great!
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