Hi ,
Please can I have some help with this demonstration:
Let a#0 ( #= different)
Show that if a x b = a x c and a.b=a.c, then b=c ( Hint: Cross both sides of the first equation with a)

When I cross by a ( as the hint suggests) , I found 0=0 ??

thank you

 

Originally posted by braddy@Oct 16 2005, 05:51 PM
Hi ,
Please can I have some help with this demonstration:
Let a#0 ( #= different)
Show that if a x b = a x c and a.b=a.c, then b=c ( Hint: Cross both sides of the first equation with a)

When I cross by a ( as the hint suggests) , I found 0=0 ??

thank you

[post=11036]Quoted post[/post]​

Try dividing both sides of the first equation by a. (What do you get when you divide a by a?)