DC parallel RLC circuit. (Steady State)

Discussion in 'General Electronics Chat' started by NewGuy01, Aug 9, 2009.

  1. NewGuy01

    Thread Starter New Member

    Aug 9, 2009
    5
    0
    Hi,
    I was wondering could anyone help me understanding this circuit.
    http://www.flickr.com/photos/41254456@N05/3804091838/

    Im looking for the initial states of the capacitor and inductor at steady state. (t<0)
    As far as I know, to analyse this I have to replace the capacitor with an open circuit and the inductor with a short circuit. Doing this yields 10v across the capacitor and 1 amp through the inductor.

    Am I doing this right? Does R3 (the 30Ω resistor) have any effect on the circuit in steady state?

    Any help is appreciated...
     
  2. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    You appear to be off to a proper start.

    R3 does not participate in the steady-state conditions since the capacitor will have been fully charged to the 10 Vdc consistent with the voltage at the intersection of the two 10 ohm resistors.

    hgmjr
     
  3. NewGuy01

    Thread Starter New Member

    Aug 9, 2009
    5
    0
    Brilliant! Thanks a mil...
     
Loading...