dc offset

Discussion in 'Homework Help' started by joka2188, Nov 11, 2006.

  1. joka2188

    Thread Starter New Member

    Nov 10, 2006
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    is there an equation for calculating the dc offset of a square wave?
     
  2. hgmjr

    Moderator

    Jan 28, 2005
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    Can you be a little more specific?

    hgmjr
     
  3. Papabravo

    Expert

    Feb 24, 2006
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    Code ( (Unknown Language)):
    1.  
    2. (Vmax + Vmin) / 2
    3.  
     
  4. joka2188

    Thread Starter New Member

    Nov 10, 2006
    9
    0
    thanks 4 dat, much appreciated
     
  5. pebe

    AAC Fanatic!

    Oct 11, 2004
    628
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    That formula assumes equal mark/space ratio.
     
  6. Papabravo

    Expert

    Feb 24, 2006
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    Last time I looked a square wave had a 50% duty cycle or equal mark space ratio as you so quaintly put it.
     
  7. Dave

    Retired Moderator

    Nov 17, 2003
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    I agree that a typical square wave has a 50% duty cycle. I think the case pebe is refering to is important for digital signals where the duty cycle may be anything between 0-100% for a given period. For example:

    If the total time period of the digital signal is x

    The digital signal is at Vmax for y periods of x

    And the digital signal is at Vmin for z periods of x

    Where x = y + z

    Then the DC offset is calulated by:

    (x*Vmax + y*Vmin)/x

    This is a general solution of which the one Papabravo gave above is a spcial case where the duty cycle is 50%

    Dave
     
  8. hgmjr

    Moderator

    Jan 28, 2005
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    When I asked joka2188 for a few more specifics, I was looking for a confirmation that the square-wave in which he was interested had a 50% duty-cycle.

    While all answers thus far provided are accurate, the general case that Dave has provided covers all contingencies nicely.

    hgmjr
     
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