Hi Can anyone explain to me how they found the solutions for the three unknown currents in the branch current method analysis in Chapter 10 step by step?
If you mean the equations then its fairly simple.Use equation 3 and express I3=7-2I2.
next I1=I2-I3 from eq 1.Use eq 2 and replace 11 and I2 in terms of I3.solve for I3 and so on.
So in the KVL equation 4I1 + 2I2 + 0I3=28 I subtract 2I2 from both sides and 0I3 from both sides like this 4I1=28 - 2I2 - 0I3??
But how do I isolate I1 on the left side of the equation? Do I divide the whole equation on the right side by 4, and on the left side, to isolate I1 on the left side?