I am making a Wind turbine power plant prototype for my project work
My generator is DC.actually its DC motor but it can be used as gen.1900 rpm rated with 24V and 2.5 A current.Problem is not all time wind gives enough rpm.But the charge controller i am using takes 24V constant to charge lead acid battery.so i need a DC DC booster.i will control the pulse width via micro controller.
My basic design is attached here.
using this equ i took min l value. i used min load current 2A and D i used when the worst case voltage is found as i got 7V and have to boost to 24V.
C=D/(2*f*R) here R is the load.
My problems are
1.while simulation i saw output voltage is dependent on L value.for safety i used 980uH that's greater than min L value and D=0.5 always.I saw it can perfectly boost 7 to 24 but while if 24V is given it gives 53V instead of 48V.
2.Output is very much depended on R value.If i use R=100 ohm it gives good result.But if i use R=500 ohm it cant even boost 7V to 14V for D=0.5,instead it gives 11V.
3.In lab i used this circuit to test but the IRF840 cant switch in 40K.whats the problem?
4.I burned 2 IRF840 though i used protection diode.but in lab source i used only 10V and 2A current.why IRF840 burns?
that's a lengthy post.But please someone help me.
My generator is DC.actually its DC motor but it can be used as gen.1900 rpm rated with 24V and 2.5 A current.Problem is not all time wind gives enough rpm.But the charge controller i am using takes 24V constant to charge lead acid battery.so i need a DC DC booster.i will control the pulse width via micro controller.
My basic design is attached here.
using this equ i took min l value. i used min load current 2A and D i used when the worst case voltage is found as i got 7V and have to boost to 24V.
C=D/(2*f*R) here R is the load.
My problems are
1.while simulation i saw output voltage is dependent on L value.for safety i used 980uH that's greater than min L value and D=0.5 always.I saw it can perfectly boost 7 to 24 but while if 24V is given it gives 53V instead of 48V.
2.Output is very much depended on R value.If i use R=100 ohm it gives good result.But if i use R=500 ohm it cant even boost 7V to 14V for D=0.5,instead it gives 11V.
3.In lab i used this circuit to test but the IRF840 cant switch in 40K.whats the problem?
4.I burned 2 IRF840 though i used protection diode.but in lab source i used only 10V and 2A current.why IRF840 burns?
that's a lengthy post.But please someone help me.
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