Hello,
I was just hoping someone could do a sanity check on the attached question.
Using Kirchoffs voltage law on the top part of the circuit, it seems there must be 27V across the 9 ohm resistor which would put -15V across the 3 ohm resistor. This means 5A for I2 is flowing into the node. When we add this to the 3A of I1 this will give us a value of 8A for I3. Does this seem to work out?
many thanks
Jim
I was just hoping someone could do a sanity check on the attached question.
Using Kirchoffs voltage law on the top part of the circuit, it seems there must be 27V across the 9 ohm resistor which would put -15V across the 3 ohm resistor. This means 5A for I2 is flowing into the node. When we add this to the 3A of I1 this will give us a value of 8A for I3. Does this seem to work out?
many thanks
Jim
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