Cut-off or Corner Frequency

Discussion in 'Homework Help' started by kaname08, Feb 11, 2012.

  1. kaname08

    Thread Starter Member

    Sep 22, 2010
    37
    0
    HI everyone, i really really need your help guys, we are about to do a small signal amplifier, but i need to know what coupling and bypass capacitor to use,so in order for me to solve it i need to know the corner or cut-off frequency to be used base on this formula :

    Ce2 = 1/(2*pi * FL * Xce2)

    pls help me guys,how will i get the frequency??,,,,

    thank you in advance..
     
  2. Audioguru

    New Member

    Dec 20, 2007
    9,411
    896
    One capacitor in the signal circuit reduces the output -3dB (x 0.707) which is called the cutoff frequency. Two capacitors (an input capacitor and an output capacitor) cause a reduction of -6dB so their values must be doubled for the entire amplifier to have the required low cutoff frequency.
    The formula for frequency is 1/2 x pi x RC.
     
  3. crutschow

    Expert

    Mar 14, 2008
    13,042
    3,243
    To clarify, that should be 1/(2 x pi x RC). ;)
     
  4. kaname08

    Thread Starter Member

    Sep 22, 2010
    37
    0
    but i still dont have a Capacitance and where will i get this resistor??
     
  5. Audioguru

    New Member

    Dec 20, 2007
    9,411
    896
    You use simple arithmatic to calculate the resistor and capacitor values. Then you buy them.
     
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