Current

Discussion in 'Homework Help' started by Lexi, Jan 4, 2009.

  1. Lexi

    Thread Starter New Member

    Jan 4, 2009
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    Given a 60 hz series circuit with a capacitive device having an impedance of Z=8-j9 ohms and an inductor having an inductance of 0.01327 and a resistance of 4 ohms, what is the current due to a 30 V signal?
     
  2. beenthere

    Retired Moderator

    Apr 20, 2004
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  3. Wendy

    Moderator

    Mar 24, 2008
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    What is your answer?
     
  4. mik3

    Senior Member

    Feb 4, 2008
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    Are they connected in series or in parallel?
     
  5. Lexi

    Thread Starter New Member

    Jan 4, 2009
    6
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    Series........
     
  6. mik3

    Senior Member

    Feb 4, 2008
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    capacitor impedance=8-j9 ohm

    inductor impedance=j*2*pi*f*L=5 ohm

    resistor impedance=4 ohm

    Add the above impedances by using complex numbers, then convert the result into polar form and finally divide the voltage by the magnitude of the total impedance to find the current. If you want find the angle too.
     
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