Hello, I know this is a silly question but it strikes me again!
The attached file is crossed coupled oscilator. The circuit oscilates at f= 1/2π√LC . At the frequency the equivalent resistance of R, L, C is equal to R, then how is it possible to create a sin signal at the output as in the picture?
The attached file is crossed coupled oscilator. The circuit oscilates at f= 1/2π√LC . At the frequency the equivalent resistance of R, L, C is equal to R, then how is it possible to create a sin signal at the output as in the picture?
Attachments
-
23.9 KB Views: 51