Ok so I just did the following measurements:Take an Ohmmeter. Measure between IN- and OUT-. If the resistance is ∞, then you could use a low-side switch...
The fact that there is a DEAD SHORT from Vin- to Vout- means that it is NOT a transformer-isolated switcher. This means that to switch it on/off with an external FET, the FET has to break the Vin+ line, not the Vin- line.Ok so I just did the following measurements:
Vin(-) and Vout(-) = 0Ω
Vin(+) and Vin(-) = 5kΩ.
Vout(+) and Vout (-)= 121MΩ
Vin(+) and Vout(+) = 0Ω
Can you explain what does it mean that there is no resistance ? I mean, why would an infinite resistance mean that I CAN make low-side connection?
From what you guys explained, it seems like it can only be connected as a high side switch.
Ok, I just wanted to know what it meant physically, so thanks for the explanation!The fact that there is a DEAD SHORT from Vin- to Vout- means that it is NOT a transformer-isolated switcher. This means that to switch it on/off with an external FET, the FET has to break the Vin+ line, not the Vin- line.
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